33:T491,where

a_{P}=

Pseudoforce or centrifugal force34:T24cb,

\theta=\tan ^{-1}\left(\frac{a_{P}}{g}\right)=\tan ^{-1}\left(\frac{v^{2}}{R g}\right)=\tan ^{-1}\left(\frac{400}{40 \times 10}\right)

=45^{\circ}

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