MathematicsMedium89×since 2002Q5449A data consists of n observations : x₁, x₂, . . . . . . ., x_n. If ∑i=1n(xi+1)2=9n\sum\limits_{i = 1}^n {{{\left( {{x_i} + 1} \right)}^2}} = 9ni=1∑n(xi+1)2=9n and ∑i=1n(xi−1)2=5n,\sum\limits_{i = 1}^n {{{\left( {{x_i} - 1} \right)}^2}} = 5n,i=1∑n(xi−1)2=5n, then the standard deviation of this data is :A2B5\sqrt 55C5D7\sqrt 77Check answerSkip