PhysicsEasy105×since 2002Q7107A prism of refractive index μ\muμ and angle of prism A is placed in the position of minimum angle of deviation. If minimum angle of deviation is also A, then in terms of refractive indexA2cos−1(μ2)2{\cos ^{ - 1}}\left( {{\mu \over 2}} \right)2cos−1(2μ)Bsin−1(μ2){\sin ^{ - 1}}\left( {{\mu \over 2}} \right)sin−1(2μ)Csin−1(μ−12){\sin ^{ - 1}}\left( {\sqrt {{{\mu - 1} \over 2}} } \right)sin−1(2μ−1)Dcos−1(μ2){\cos ^{ - 1}}\left( {{\mu \over 2}} \right)cos−1(2μ)Check answerSkip