PhysicsMedium159×since 2002Q7258A straight rod of length L extends from x = a to x = L + a. The gravitational force it exerts on a point mass 'm' at x = 0, if the mass per unit length of the rod is A + Bx² , is given by :AGm[A(1a−1a+L)−BL]Gm\left[ {A\left( {{1 \over a} - {1 \over {a + L}}} \right) - BL} \right]Gm[A(a1−a+L1)−BL]BGm[A(1a−1a+L)+BL]Gm\left[ {A\left( {{1 \over a} - {1 \over {a + L}}} \right) + BL} \right]Gm[A(a1−a+L1)+BL]CGm[A(1a+L−1a)+BL]Gm\left[ {A\left( {{1 \over {a + L}} - {1 \over a}} \right) + BL} \right]Gm[A(a+L1−a1)+BL]DGm[A(1a+L−1a)−BL]Gm\left[ {A\left( {{1 \over {a + L}} - {1 \over a}} \right) - BL} \right]Gm[A(a+L1−a1)−BL]Check answerSkip