PhysicsMedium55×since 2003Q6690A transformer has an efficiency of 80%80 \%80% and works at 10 V10 \mathrm{~V}10 V and 4 kW4 \mathrm{~kW}4 kW. If the secondary voltage is 240 V240 \mathrm{~V}240 V, then the current in the secondary coil is :A1.33 A1.33 \mathrm{~A}1.33 AB13.33 A13.33 \mathrm{~A}13.33 AC1.59 A1.59 \mathrm{~A}1.59 AD15.1 A15.1 \mathrm{~A}15.1 ACheck answerSkip