PhysicsEasy94×since 2002Q5887An AC current is given by I = I₁ sinω\omegaωt + I₂ cosω\omegaωt. A hot wire ammeter will give a reading :AI1+I22{{{I_1} + {I_2}} \over {\sqrt 2 }}2I1+I2BI12−I222\sqrt {{{I_1^2 - I_2^2} \over 2}}2I12−I22CI12+I222\sqrt {{{I_1^2 + I_2^2} \over 2}}2I12+I22DI1+I222{{{I_1} + {I_2}} \over {2\sqrt 2 }}22I1+I2Check answerSkip