MathematicsHard89×since 2002Q5489Consider 10 observations x1,x2,…,x10x_1, x_2, \ldots, x_{10}x1,x2,…,x10 such that ∑i=110(xi−α)=2\sum\limits_{i=1}^{10}\left(x_i-\alpha\right)=2i=1∑10(xi−α)=2 and ∑i=110(xi−β)2=40\sum\limits_{i=1}^{10}\left(x_i-\beta\right)^2=40i=1∑10(xi−β)2=40, where α,β\alpha, \betaα,β are positive integers. Let the mean and the variance of the observations be 65\frac{6}{5}56 and 8425\frac{84}{25}2584 respectively. Then βα\frac{\beta}{\alpha}αβ is equal to :A2B1C52\frac{5}{2}25D32\frac{3}{2}23Check answerSkip