ChemistryMedium88×since 2002Q2078Consider the reaction 4HNO3(1)+3KCl(s)→Cl2( g)+NOCl(g)+2H2O(g)+3KNO3( s)4 \mathrm{HNO}_{3}(1)+3 \mathrm{KCl}(\mathrm{s}) \rightarrow \mathrm{Cl}_{2}(\mathrm{~g})+\mathrm{NOCl}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})+3 \mathrm{KNO}_{3}(\mathrm{~s})4HNO3(1)+3KCl(s)→Cl2( g)+NOCl(g)+2H2O(g)+3KNO3( s) The amount of HNO3\mathrm{HNO}_{3}HNO3 required to produce 110.0 g110.0 \mathrm{~g}110.0 g of KNO3\mathrm{KNO}_{3}KNO3 is (Given: Atomic masses of H,O,N\mathrm{H}, \mathrm{O}, \mathrm{N}H,O,N and K\mathrm{K}K are 1,16,141,16,141,16,14 and 39, respectively.)A32.2 gB69.4 gC91.5 gD162.5 gCheck answerSkip