MathematicsMedium129×since 2002Q5109Difference between the corresponding roots of x2+ax+b=0{x^2} + ax + b = 0x2+ax+b=0 and x2+bx+a=0{x^2} + bx + a = 0x2+bx+a=0 is same and a≠b,a \ne b,a=b, thenAa+b+4=0a + b + 4 = 0a+b+4=0Ba+b−4=0a + b - 4 = 0a+b−4=0Ca−b−4=0a - b - 4 = 0a−b−4=0Da−b+4=0a - b + 4 = 0a−b+4=0Check answerSkip