ChemistryEasy71×since 2002Q504For a reaction 12A→2B{1 \over 2}A \to 2B21A→2B rate of disappearance of ‘A’ is related to the rate of appearance of ‘B’ by the expressionA−d[A]dt- {{d[A]} \over {dt}}−dtd[A] = 12d[B]dt{1 \over 2}{{d[B]} \over {dt}}21dtd[B]B−d[A]dt- {{d[A]} \over {dt}}−dtd[A] = 14d[B]dt{1 \over 4}{{d[B]} \over {dt}}41dtd[B]C−d[A]dt- {{d[A]} \over {dt}}−dtd[A] = d[B]dt{{d[B]} \over {dt}}dtd[B]D−d[A]dt- {{d[A]} \over {dt}}−dtd[A] = 4d[B]dt4{{d[B]} \over {dt}}4dtd[B]Check answerSkip