MathematicsMedium210×since 2002Q3301For x ∈\in∈ R, x ≠\ne= 0, if y(x) is a differentiable function such that x ∫1xy\int\limits_1^x y1∫xy (t) dt = (x + 1) ∫1xty\int\limits_1^x ty1∫xty (t) dt, then y (x) equals : (where C is a constant.)ACxe−1x{C \over x}{e^{ - {1 \over x}}}xCe−x1BCx2e−1x{C \over {{x^2}}}{e^{ - {1 \over x}}}x2Ce−x1CCx3e−1x{C \over {{x^3}}}{e^{ - {1 \over x}}}x3Ce−x1DCx3 1exC{x^3}\,{1 \over {{e^x}}}Cx3ex1Check answerSkip