Given the equilibrium constant: K_C of the reaction : Cu(s) + 2Ag⁺ (aq) … Cu²⁺ (aq) + 2Ag(s) is 10 … 10¹⁵, calculate the E… of this reaciton at 298 K [2.303 … at 298 K = 0.059V]

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Electrochemistry

JEE Main 2019 · 11 Jan, Evening shift · Q990

ChemistryMedium86×since 2002Q990

Given the equilibrium constant: K_C of the reaction : Cu(s) + 2Ag⁺ (aq)

\to

Cu²⁺ (aq) + 2Ag(s) is 10

\times

10¹⁵, calculate the E

_{cell}^0

of this reaciton at 298 K [2.303

{{RT} \over F}

at 298 K = 0.059V]