MathematicsMedium45×since 2004Q5655If sinθ+cosθ=12\sin \theta + \cos \theta = {1 \over 2}sinθ+cosθ=21, then 16(sin(2θ\thetaθ) + cos(4θ\thetaθ) + sin(6θ\thetaθ)) is equal to :A23B−-−27C−-−23D27Check answerSkip