MathematicsEasy178×since 2002Q5341If an=−24n2−16n+15{a_n} = {{ - 2} \over {4{n^2} - 16n + 15}}an=4n2−16n+15−2, then a1+a2 + .... + a25{a_1} + {a_2}\, + \,....\, + \,{a_{25}}a1+a2+....+a25 is equal to :A51144{{51} \over {144}}14451B49138{{49} \over {138}}13849C50141{{50} \over {141}}14150D52147{{52} \over {147}}14752Check answerSkip