MathematicsHard64×since 2002Q3006If (30C1)2+2(30C2)2+3(30C3)2 + ... + 30(30C30)2=α60!(30!)2{({}^{30}{C_1})^2} + 2{({}^{30}{C_2})^2} + 3{({}^{30}{C_3})^2}\, + \,...\, + \,30{({}^{30}{C_{30}})^2} = {{\alpha 60!} \over {{{(30!)}^2}}}(30C1)2+2(30C2)2+3(30C3)2+...+30(30C30)2=(30!)2α60! then α\alphaα is equal to :A30B10C15D60Check answerSkip