MathematicsMedium129×since 2002Q5111If α≠β\alpha \ne \betaα=β but α2=5α−3{\alpha ^2} = 5\alpha - 3α2=5α−3 and β2=5β−3{\beta ^2} = 5\beta - 3β2=5β−3 then the equation having α/β\alpha /\betaα/β and β/α \beta /\alpha \,\,β/α as its roots isA3x2−19x+3=03{x^2} - 19x + 3 = 03x2−19x+3=0B3x2+19x−3=03{x^2} + 19x - 3 = 03x2+19x−3=0C3x2−19x−3=03{x^2} - 19x - 3 = 03x2−19x−3=0Dx2−5x+3=0{x^2} - 5x + 3 = 0x2−5x+3=0Check answerSkip