MathematicsMedium38×since 2002Q3623If dydx+2x−y(2y−1)2x−1=0{{dy} \over {dx}} + {{{2^{x - y}}({2^y} - 1)} \over {{2^x} - 1}} = 0dxdy+2x−12x−y(2y−1)=0, x, y > 0, y(1) = 1, then y(2) is equal to :A2+log232 + {\log _2}32+log23B2+log322 + {\log _3}22+log32C2−log322 - {\log _3}22−log32D2−log232 - {\log _2}32−log23Check answerSkip