MathematicsMedium129×since 2002Q5125If for a positive integer n, the quadratic equation x(x+1)+(x+1)(x+2)x\left( {x + 1} \right) + \left( {x + 1} \right)\left( {x + 2} \right)x(x+1)+(x+1)(x+2)+....+(x+n−1‾)(x+n)+ .... + \left( {x + \overline {n - 1} } \right)\left( {x + n} \right)+....+(x+n−1)(x+n)=10n= 10n=10n has two consecutive integral solutions, then n is equal to :A9B10C11D12Check answerSkip