MathematicsMedium64×since 2004Q4028If ∫cosx−sinx8−sin2xdx=asin−1(sinx+cosxb)+c\int {{{\cos x - \sin x} \over {\sqrt {8 - \sin 2x} }}} dx = a{\sin ^{ - 1}}\left( {{{\sin x + \cos x} \over b}} \right) + c∫8−sin2xcosx−sinxdx=asin−1(bsinx+cosx)+c, where c is a constant of integration, then the ordered pair (a, b) is equal to :A(-1, 3)B(1, 3)C(1, -3)D(3, 1)Check answerSkip