MathematicsEasy210×since 2002Q3335If ∫0πxf(sinx)dx=A∫0π/2f(sinx)dx,\int\limits_0^\pi {xf\left( {\sin x} \right)dx = A\int\limits_0^{\pi /2} {f\left( {\sin x} \right)dx,} }0∫πxf(sinx)dx=A0∫π/2f(sinx)dx, then AAA isA2π2\pi2πBπ\piπCπ4{\pi \over 4}4πD000Check answerSkip