MathematicsMedium64×since 2004Q4027If ∫sin−1(x1+x)dx\int {{{\sin }^{ - 1}}\left( {\sqrt {{x \over {1 + x}}} } \right)} dx∫sin−1(1+xx)dx = A(x)tan−1(x){\tan ^{ - 1}}\left( {\sqrt x } \right)tan−1(x) + B(x) + C, where C is a constant of integration, then the ordered pair (A(x), B(x)) can be :A(x + 1, -x{\sqrt x }x)B(x + 1, x{\sqrt x }x)C(x - 1, -x{\sqrt x }x)D(x - 1, x{\sqrt x }x)Check answerSkip