MathematicsMedium53×since 2002Q3235If (1+i1−i)x=1{\left( {{{1 + i} \over {1 - i}}} \right)^x} = 1(1−i1+i)x=1 then :Ax = 2n + 1, where n is any positive integerBx = 4n , where n is any positive integerCx = 2n, where n is any positive integerDx = 4n + 1, where n is any positive integer.Check answerSkip