MathematicsEasy74×since 2004Q3721If m is the slope of a common tangent to the curves x216+y29=1{{{x^2}} \over {16}} + {{{y^2}} \over 9} = 116x2+9y2=1 and x2+y2=12{x^2} + {y^2} = 12x2+y2=12, then 12m212{m^2}12m2 is equal to :A6B9C10D12Check answerSkip