MathematicsEasy179×since 2002Q4285If limx→0sin−1x−tan−1x3x3\mathop {\lim }\limits_{x \to 0} {{{{\sin }^{ - 1}}x - {{\tan }^{ - 1}}x} \over {3{x^3}}}x→0lim3x3sin−1x−tan−1x is equal to L, then the value of (6L + 1) isA16{1 \over 6}61B12{1 \over 2}21C6D2Check answerSkip