MathematicsEasy210×since 2002Q3452If [t] denotes the greatest integer ≤t\le \mathrm{t}≤t, then the value of 3(e−1)e∫12x2e[x]+[x3]dx{{3(e - 1)} \over e}\int\limits_1^2 {{x^2}{e^{[x] + [{x^3}]}}dx}e3(e−1)1∫2x2e[x]+[x3]dx is :Ae8−e\mathrm{e^8-e}e8−eBe7−1\mathrm{e^7-1}e7−1Ce9−e\mathrm{e^9-e}e9−eDe8−1\mathrm{e^8-1}e8−1Check answerSkip