MathematicsMedium64×since 2002Q2939If the coefficient of x15x^{15}x15 in the expansion of (ax3+1 bx1/3)15\left(\mathrm{a} x^{3}+\frac{1}{\mathrm{~b} x^{1 / 3}}\right)^{15}(ax3+ bx1/31)15 is equal to the coefficient of x−15x^{-15}x−15 in the expansion of (ax1/3−1bx3)15\left(a x^{1 / 3}-\frac{1}{b x^{3}}\right)^{15}(ax1/3−bx31)15, where aaa and bbb are positive real numbers, then for each such ordered pair (a,b)(\mathrm{a}, \mathrm{b})(a,b) :Aa = 3bBab = 1Cab = 3Da = bCheck answerSkip