MathematicsMedium64×since 2002Q2907If the coefficients of r^th, (r+1)^th, and (r + 2)^th terms in the binomial expansion of (1+y)m{{\rm{(1 + y )}}^m}(1+y)m are in A.P., then m and r satisfy the equationAm2−m(4r−1)+4 r2−2=0{m^2} - m(4r - 1) + 4\,{r^2} - 2 = 0m2−m(4r−1)+4r2−2=0Bm2−m(4r+1)+4 r2+2=0{m^2} - m(4r + 1) + 4\,{r^2} + 2 = 0m2−m(4r+1)+4r2+2=0Cm2−m(4r+1)+4 r2−2=0{m^2} - m(4r + 1) + 4\,{r^2} - 2 = 0m2−m(4r+1)+4r2−2=0Dm2−m(4r−1)+4 r2+2=0{m^2} - m(4r - 1) + 4\,{r^2} + 2 = 0m2−m(4r−1)+4r2+2=0Check answerSkip