PhysicsMedium159×since 2002Q7236If the gravitational field in the space is given as (−Kr2)\left(-\frac{K}{r^{2}}\right)(−r2K). Taking the reference point to be at r=2 cm\mathrm{r}=2 \mathrm{~cm}r=2 cm with gravitational potential V=10 J/kg\mathrm{V}=10 \mathrm{~J} / \mathrm{kg}V=10 J/kg. Find the gravitational potential at r=3 cm\mathrm{r}=3 \mathrm{~cm}r=3 cm in SI unit (Given, that K=6 Jcm/kg\mathrm{K}=6 \mathrm{~Jcm} / \mathrm{kg}K=6 Jcm/kg)A9B11C10D12Check answerSkip