MathematicsMedium249×since 2002Q2484If the line x−12=y+13=z−14{{x - 1} \over 2} = {{y + 1} \over 3} = {{z - 1} \over 4}2x−1=3y+1=4z−1 and x−31=y−k2=z1{{x - 3} \over 1} = {{y - k} \over 2} = {z \over 1}1x−3=2y−k=1z intersect, then kkk is equal to :A−1-1−1B29{2 \over 9}92C92{9 \over 2}29D000Check answerSkip