ChemistryMedium113×since 2002Q2186If the radius of the first orbit of hydrogen atom is α0\alpha_{0}α0, then de Broglie's wavelength of electron in 3rd 3^{\text {rd }}3rd orbit is :Aπα36\frac{\pi \alpha^{3}}{6}6πα3B3πα03\pi\alpha_03πα0C6πα06\pi\alpha_06πα0Dπα33\frac{\pi \alpha^{3}}{3}3πα3Check answerSkip