MathematicsMedium38×since 2002Q3543If the solution of the differential equation dydx+ex(x2−2)y=(x2−2x)(x2−2)e2x{{dy} \over {dx}} + {e^x}\left( {{x^2} - 2} \right)y = \left( {{x^2} - 2x} \right)\left( {{x^2} - 2} \right){e^{2x}}dxdy+ex(x2−2)y=(x2−2x)(x2−2)e2x satisfies y(0)=0y(0) = 0y(0)=0, then the value of y(2) is _______________.A−-−1B1C0DeCheck answerSkip