MathematicsHard129×since 2002Q5155If the sum of the squares of the reciprocals of the roots α\alphaα and β\betaβ of the equation 3x² + λ\lambdaλx −-− 1 = 0 is 15, then 6(α\alphaα³ + β\betaβ³)² is equal to :A18B24C36D96Check answerSkip