MathematicsMedium244×since 2002Q4623If the system of equations x+2y+3z=3x+2y+3z=3x+2y+3z=3 4x+3y−4z=44x+3y-4z=44x+3y−4z=4 8x+4y−λz=9+μ8x+4y-\lambda z=9+\mu8x+4y−λz=9+μ has infinitely many solutions, then the ordered pair (λ,μ\lambda,\muλ,μ) is equal to :A(725,215)\left( {{{72} \over 5},{{21} \over 5}} \right)(572,521)B(−725,−215)\left( { - {{72} \over 5}, - {{21} \over 5}} \right)(−572,−521)C(−725,215)\left( { - {{72} \over 5},{{21} \over 5}} \right)(−572,521)D(725,−215)\left( {{{72} \over 5}, - {{21} \over 5}} \right)(572,−521)Check answerSkip