MathematicsMedium244×since 2002Q4638If the system of equations x+(2sinα)y+(2cosα)z=0x+(cosα)y+(sinα)z=0x+(sinα)y−(cosα)z=0\begin{aligned} & x+(\sqrt{2} \sin \alpha) y+(\sqrt{2} \cos \alpha) z=0 \\ & x+(\cos \alpha) y+(\sin \alpha) z=0 \\ & x+(\sin \alpha) y-(\cos \alpha) z=0 \end{aligned}x+(2sinα)y+(2cosα)z=0x+(cosα)y+(sinα)z=0x+(sinα)y−(cosα)z=0 has a non-trivial solution, then α∈(0,π2)\alpha \in\left(0, \frac{\pi}{2}\right)α∈(0,2π) is equal to :A5π24\frac{5 \pi}{24}245πB11π24\frac{11 \pi}{24}2411πC7π24\frac{7 \pi}{24}247πD3π4\frac{3 \pi}{4}43πCheck answerSkip