MathematicsEasy175×since 2002Q2768If the tangent to the curve y=xx2−3y = {x \over {{x^2} - 3}}y=x2−3x , x∈ρ,(x≠±3)x \in \rho ,\left( {x \ne \pm \sqrt 3 } \right)x∈ρ,(x=±3), at a point (α\alphaα, β\betaβ) ≠\ne= (0, 0) on it is parallel to the line 2x + 6y – 11 = 0, then :A| 6α\alphaα + 2β\betaβ | = 9B| 2α\alphaα + 6β\betaβ | = 11C| 2α\alphaα + 6β\betaβ | = 19D| 6α\alphaα + 2β\betaβ | = 19Check answerSkip