MathematicsMedium63×since 2002Q3683If logey=3sin−1x\log _e y=3 \sin ^{-1} xlogey=3sin−1x, then (1−x2)y′′−xy′(1-x^2) y^{\prime \prime}-x y^{\prime}(1−x2)y′′−xy′ at x=12x=\frac{1}{2}x=21 is equal toA9eπ/29 e^{\pi / 2}9eπ/2B9eπ/69 e^{\pi / 6}9eπ/6C3eπ/23 e^{\pi / 2}3eπ/2D3eπ/63 e^{\pi / 6}3eπ/6Check answerSkip