PhysicsEasy65×since 2002Q7834If t=x+4\mathrm{t}=\sqrt{x}+4t=x+4, then (dx dt)t=4\left(\frac{\mathrm{d} x}{\mathrm{~d} t}\right)_{\mathrm{t}=4}( dtdx)t=4 is :A4BzeroC8D16Check answerSkip