MathematicsMedium38×since 2002Q3578If xdydx=y(logy−logx+1),x{{dy} \over {dx}} = y\left( {\log y - \log x + 1} \right),xdxdy=y(logy−logx+1), then the solution of the equation is :Aylog(xy)=cxy\log \left( {{x \over y}} \right) = cxylog(yx)=cxBxlog(yx)=cyx\log \left( {{y \over x}} \right) = cyxlog(xy)=cyClog(yx)=cx\log \left( {{y \over x}} \right) = cxlog(xy)=cxDlog(xy)=cy\log \left( {{x \over y}} \right) = cylog(yx)=cyCheck answerSkip