MathematicsMedium210×since 2002Q3421If [x] is the greatest integer ≤\le≤ x, then π2∫02(sinπx2)(x−[x])[x]dx{\pi ^2}\int\limits_0^2 {\left( {\sin {{\pi x} \over 2}} \right)(x - [x]} {)^{[x]}}dxπ20∫2(sin2πx)(x−[x])[x]dx is equal to :A2(π\piπ −-− 1)B4(π\piπ −-− 1)C4(π\piπ + 1)D2(π\piπ + 1)Check answerSkip