MathematicsMedium38×since 2002Q3595If y = y(x) is the solution of the differential equation 5+ex2+y.dydx+ex=0{{5 + {e^x}} \over {2 + y}}.{{dy} \over {dx}} + {e^x} = 02+y5+ex.dxdy+ex=0 satisfying y(0) = 1, then a value of y(log_e13) is :A-1B1C0D2Check answerSkip