MathematicsMedium75×since 2002Q4871In a binomial distribution B(n,p=14),B\left( {n,p = {1 \over 4}} \right),B(n,p=41), if the probability of at least one success is greater than or equal to 910,{9 \over {10}},109, then nnn is greater than :A1log104+log103{1 \over {\log _{10}^4 + \log _{10}^3}}log104+log1031B9log104−log103{9 \over {\log _{10}^4 - \log _{10}^3}}log104−log1039C4log104−log103{4 \over {\log _{10}^4 - \log _{10}^3}}log104−log1034D1log104−log103{1 \over {\log _{10}^4 - \log _{10}^3}}log104−log1031Check answerSkip