MathematicsMedium202×since 2002Q5775In a triangle ABC, if ∣BC→∣=3\left| {\overrightarrow {BC} } \right| = 3BC=3, ∣CA→∣=5\left| {\overrightarrow {CA} } \right| = 5CA=5 and ∣BA→∣=7\left| {\overrightarrow {BA} } \right| = 7BA=7, then the projection of the vector BA→\overrightarrow {BA}BA on BC→\overrightarrow {BC}BC is equal to :A192{{19} \over 2}219B132{{13} \over 2}213C112{{11} \over 2}211D152{{15} \over 2}215Check answerSkip