MathematicsHard202×since 2002Q5774In a triangle ABC, if ∣BC→∣=8,∣CA→∣=7,∣AB→∣=10|\overrightarrow {BC} | = 8,|\overrightarrow {CA} | = 7,|\overrightarrow {AB} | = 10∣BC∣=8,∣CA∣=7,∣AB∣=10, then the projection of the vector AB→\overrightarrow {AB}AB on AC→\overrightarrow {AC}AC is equal to :A254{{25} \over 4}425B12720{{127} \over 20}20127C8514{{85} \over 14}1485D11516{{115} \over 16}16115Check answerSkip