MathematicsMedium19×since 2002Q5037In a triangle ABCABCABC, medians ADADAD and BEBEBE are drawn. If AD=4AD=4AD=4, ∠DAB=π6\angle DAB = {\pi \over 6}∠DAB=6π and ∠ABE=π3\angle ABE = {\pi \over 3}∠ABE=3π, then the area of the ∠ΔABC\angle \Delta ABC∠ΔABC is :A643{{64} \over 3}364B83{8 \over 3}38C163{{16} \over 3}316D3233{{32} \over {3\sqrt 3 }}3332Check answerSkip