MathematicsHard64×since 2002Q2926In the expansion of (xcosθ+1xsinθ)16{\left( {{x \over {\cos \theta }} + {1 \over {x\sin \theta }}} \right)^{16}}(cosθx+xsinθ1)16, if ℓ1{\ell _1}ℓ1 is the least value of the term independent of x when π8≤θ≤π4{\pi \over 8} \le \theta \le {\pi \over 4}8π≤θ≤4π and ℓ2{\ell _2}ℓ2 is the least value of the term independent of x when π16≤θ≤π8{\pi \over {16}} \le \theta \le {\pi \over 8}16π≤θ≤8π, then the ratio ℓ2{\ell _2}ℓ2 : ℓ1{\ell _1}ℓ1 is equal to :A8 : 1B16 : 1C1 : 8D1 : 16Check answerSkip