PhysicsEasy85×since 2002Q8508In the wave equation y=0.5sin2πλ(400t−x) my=0.5 \sin \frac{2 \pi}{\lambda}(400 \mathrm{t}-x) \,\mathrm{m}y=0.5sinλ2π(400t−x)m the velocity of the wave will be:A200 m/sB2002\sqrt22 m/sC400 m/sD4002\sqrt22 m/sCheck answerSkip