MathematicsMedium64×since 2004Q4050∫sin5x2sinx2dx\int {{{\sin {{5x} \over 2}} \over {\sin {x \over 2}}}dx}∫sin2xsin25xdx is equal to (where c is a constant of integration)A2x + sinx + 2sin2x + cBx + 2sinx + sin2x + cCx + 2sinx + 2sin2x + cD2x + sinx + sin2x + cCheck answerSkip