MathematicsMedium64×since 2002Q2925Let α\alphaα > 0, β\betaβ > 0 be such that α\alphaα³ + β\betaβ² = 4. If the maximum value of the term independent of x in the binomial expansion of (αx19+βx−16)10{\left( {\alpha {x^{{1 \over 9}}} + \beta {x^{ - {1 \over 6}}}} \right)^{10}}(αx91+βx−61)10 is 10k, then k is equal to :A176B336C352D84Check answerSkip