MathematicsMedium210×since 2002Q3405Let a be a positive real number such that ∫0aex−[x]dx=10e−9\int_0^a {{e^{x - [x]}}} dx = 10e - 9∫0aex−[x]dx=10e−9 where [ x ] is the greatest integer less than or equal to x. Then a is equal to:A10−loge(1+e)10 - {\log _e}(1 + e)10−loge(1+e)B10+loge210 + {\log _e}210+loge2C10+loge310 + {\log _e}310+loge3D10+loge(1+e)10 + {\log _e}(1 + e)10+loge(1+e)Check answerSkip