Let a function ƒ : [0, 5] … R be continuous, ƒ(1) = 3 and F be defined as : … , where … Then for the function F, the point x = 1 is :

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Definite Integration

JEE Main 2020 · 9 Jan, Evening shift · Q3307

MathematicsMedium210×since 2002Q3307

Let a function ƒ : [0, 5]

\to

R be continuous, ƒ(1) = 3 and F be defined as :

F(x) = \int\limits_1^x {{t^2}g(t)dt}

, where

g(t) = \int\limits_1^t {f(u)du}

Then for the function F, the point x = 1 is :